Heron's Formula


Heron or Hero was a Greek Mathematician who discovered a formula for the area of a triangle, tex2html_wrap_inline318 with sides

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Before giving this formula, we need a little trigonometry. We assume that you are familiar with some trigonometry, and know what is meant by the ``sine'' and the ``cosine'' of an angle. Consider tex2html_wrap_inline320 with a right angle at X and let tex2html_wrap_inline324 .

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We define tex2html_wrap_inline334 and tex2html_wrap_inline336 .




The Sine Rule

This give us the relation between the sides of a triangle, the sines of the opposite angles and the radius of the circumcircle. We consider tex2html_wrap_inline318 and draw the circumcircle. Suppose that BB' is a diameter (of length 2R).

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Join CB', and note that

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Further, note that tex2html_wrap_inline354 is a right angle. Observe that

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where, as usual, we denote BC by a.Then

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This shows that

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and so the Sine Rule is obtained.




The Cosine Rule

Consider tex2html_wrap_inline318 and draw the perpendicular line to AB through C. Suppose this line meets AB at D.

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Then

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so that

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and

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From this, by squaring the latter two equations, we get:

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Adding these together gives

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This is the Cosine Rule.




A Further Observation

Since we have found that

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we can deduce that

  eqnarray64



The Area of a Triangle

We shall use the Sine Rule to get an new formula for the area of a triangle.

picture46

The area of tex2html_wrap_inline318 is given by tex2html_wrap_inline388 base tex2html_


wrap_inline390 height. Thus

  eqnarray86

The perimeter of tex2html_wrap_inline318 is given by AB+BC+CA. The semi-perimeter is half of this value! We denote the semi-perimeter by s, so that

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Heron's Formula

We use equations (1) and (2) to get

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A similar argument gives

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and so

  eqnarray113

Using the formulae for the area of a triangle and these, we get

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This is HERON's formula. The great advantage is that the area of the triangle can be calculated solely from the knowledge of the lengths of the sides. No information about the angles is required.



Useful Trigonometric Formulae

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Heron's Formula: Part II

Here we give an algebraic derivation of Heron's Formula.

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Let CD=h, AB=c, BC=a and CA=b as usual. Then

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so that

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giving

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Squaring gives

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or

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or

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and Heron's formula follows at once.



Heron's Formula: Part III

Here we extend Heron's formula to find the area of CYCLIC quadrilaterals.Consider the cyclic quadrilateral ABCD and denote the sides and a diagonal as follows:

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We define tex2html_wrap_inline412 . Let tex2html_wrap_inline414 , so that tex2html_wrap_inline416 .

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Then, the cosine rule, applied to tex2html_wrap_inline318 and tex2html_wrap_inline440 , gives that

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Eliminating tex2html_wrap_inline442 from these equations gives

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Thus

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yielding

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Let tex2html_wrap_inline444 represent the area of tex2html_wrap_inline318 and tex2htm


l_wrap_inline448 represent the area of tex2html_wrap_inline440 .Heron's formula then gives us:

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Now

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Similarly

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Together, we now get

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so that

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From this it is very easy to obtain the following formula for the area of a cyclic quadrilateral:

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Bruce Shawyer
Thu Oct 30 09:50:33 NST 1997